How many 176 resistors are required
WebSolution Verified by Toppr Step 1 : Equivalent resistance Let n be the number of resistors to be connected in parallel Then, R 1=R 2=......=R n=R=176 Ω Now, R eq1 = R 11+ R 21 +..... R n1 ⇒ R eq1 = R 1n= 176n ⇒R eq=176/n ....(1) Step 2 : Applying Ohm’s law V=IR eq ⇒220=5R eq ⇒220=5×176/n ( Using Equation (1)) ⇒n=4 WebSolution for How many 176Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Skip to main content. close. Start your trial now! First week only $4.99! arrow ... How many 176Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Expert Solution. Want to see the full answer? Check out a sample Q&A here.
How many 176 resistors are required
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WebAns: For x number of resistors of resistance 176 Ω, Here Supply voltage, V = 220 V Current, I = 5 A Equivalent resistance of the combination = R, given as From Ohm’s law, ∴four … WebFind many great new & used options and get the best deals for Ohmite Two Ganged 35 Ohm 1.0 Amp Wire Wound Potentiometers at the best online prices at eBay! ... Vitreous Enamel Adjustable Wire-Wound Power Resistors, 100 Watts. $5.59 + $4.50 shipping. Ohmite 12 Ohm 2.04 Amp Wire Wound Potentiometer ... Minimum monthly payments are required ...
WebNow, as per Ohm’s Law, we get, V I = 176 x V I = 176 x ⇒ x = 176×5 220 = 4 x = 176 × 5 220 = 4 Hence, in order to draw the required amount of current, four 176 Ω resistors will be …
WebR_total = (R1 * R2) / (R1 + R2) Where R1 and R2 are the values of the two resistors. To calculate the number of 176 ohm resistors required in parallel to achieve a specific resistance, you need to use the following formula: WebApr 8, 2024 · Hint: The equation for the net resistance for two resistors of resistances connected in parallel hast to be used first. Further, Ohm's law and Kirchoff’s current law will also be used to find the number of resistors. Formula used: The net resistance for two resistors of three resistances \[({R_1}),({R_2})\]and \[\left( {{R_3}} \right)\] connected in …
WebMar 9, 2024 · Now for x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is 44 Ω. 1/44 = 1/176 + 1/176 + 1/176 .....χ times. 1/44 = x / 176 => x = 176/ 44 => x = 4. Therefore, 4 resistors of 176 Ω are required to draw the given amount of current. I hope, this will help you___ . Thank you
WebAre you wondering how many 176 ohm resistors in parallel are required for your circuit? This is a common … Read more. Resistor color codes. are a standard system for indicating the value of resistors in electronic circuits. Understanding how to read these codes is an essential skill for anyone working with electronic components, whether you ... territoriality in geographyWebMar 19, 2024 · For three resistors if we connect them in parallel the equivalent resistance is R 1 R = 1 R1 + 1 R2 + 1 R3 1 R = 1 R 1 + 1 R 2 + 1 R 3 For x number of resistors of resistance 176 Ω the equivalent resistance of the resistors connected in parallel is given by ohm’s law as V = IR R = V I V I Where,supply voltage, V = 220 V current I = 5A triforce floorWebApr 5, 2024 · Therefore, current through 12 Ω resistor = 0.67 A. 12. How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Suppose n resistors of 176 Ω are connected in parallel. 1/R = 1/176 + 1/176 + ……….n times 1/R = n/176 or R= 176/n Ω By Ohm’s law R=V/I 176/n = 220/5 n= (176 x 5)/220 = 4 13. territorial integrity definition for kidsWebYou are given several identical resistance each of value R=10 and each capable of carrying a maximum current of one ampere. It is required to make a suitable combination of these … triforce foldingWebJun 24, 2024 · According to Ohm’s law, V = IR Now for x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is 44 Ω. Therefore, … territorial landworks incWebI ( current ) = V (voltage ) / R ( resistance ) . hence to carry 5A at 220 V supply Resistance required V / I = 220 / 5 = 44 OHMS. In parallel circuit 1/R = 1/R1 + 1/ R2 + 1 / R3 so on …. Hence 1 / 44 = n / 176 when n = no of parallel resistance so n = 176 / … triforce floor joistsWebHow many 176Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Solution For x number of resistors of resistance 176Ω, the equivalent resistance of the resistors … triforce floor trusses