Find the result of mixing 10g of ice
WebSolution please note that mixture temperature is 100 degree celsius.i took m gram of steam and heat lost by this amount of steam is used to raise temperature of 10 g of ice from -10 to 100 degree celsius.please see heat gained by ice part i have raised its temperature to 100 so mixture temp is 100 degree .please read solution carefully. WebThe heat will come from 20 g water. Let that heat B be given by 20 grams of water to reach zero degrees. So that's it. Will be the same as M. S Delta T. M. Take the specific heat of …
Find the result of mixing 10g of ice
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WebJun 8, 2015 · Determine the result when 100g of steam at 100C is passed into a mixture of 200g of Water and 20g of ice at exactly 0C in a calorimeter which behaves thermally as if it were equvalent to 30g of water. ... Mass steam 10g at 100C Mass Water at 0C Mass Ice at 0C Mass Calorimeter at 0C(equivalent to water. Same thing except I get -2.5C. for a final ... WebStep- (i) Heat added, in raising 10 gm of Ice from —7°C to 0°C = (mass)× (sp heat of ice)× {temp. rise} = (10 gm)× (0.5 cal/gm.°C)× { (0)— (—7)} =10× (0.5)× 7 = 35 cal. Step- (ii) Heat added, in changing 10 gm of Ice at (0° C) to 10 gm of water at (0° C) = (mass)× (latent heat of fusion of ice) = (10 gm)× (80 cal/gm).= 800 calories.
WebCorrect option is C) Let the final temperature of mixture be t. Heat lost by water in calories, H 1=19×1×(30−t) =570−19t Heat taken by ice, H 2=ms iΔt+mL+ms wt =5×(0.5)20+5×80+5×1×t According to principle of calorimetry, H 1=H 2 5×(0.5)×20+5×80+5t=570−19t ⇒24t=570−450=120 ⇒t=5 Was this answer helpful? 0 0 … WebAug 17, 2024 · ICSE 10 - Physics. a calorimetry of mass 50g contains 200g of water at 30degree celcius . Calculate the final temperature of the mixture when 40g of ice at …
WebMar 15, 2024 · answered • expert verified. Find the result of mixing 10g of ice at -10 degree C with 10 g of water at 10 degree C. Specific heat cap. of ice= 2.1 J/g K. Specific latent heat of ice= 336 J/g. Specific heat cap. … WebSolution Let the whole ice melt and let the final temperature of the mixture be T o C. Amount of heat energy gained by 10 g of ice at -10 o C to raise its temperature to 0 o C= 10 × 10 …
WebWith this calculator you can determine the final temperature of a solution after mixing two or more solutions together. This is for water in liquid, gaseous (steam), or solid (ice) form. Mass units: Temperature scale: Result of mixing: of in temperature of in temperature Add another field Clear all fields
WebMar 12, 2024 · Find the result of mixing 10 gm ice at − 10 ∘ C with 10 g water at 10^\circ C. The specific heat capacity of ice is 2 .1 J g − 1 L − 1, Specific latent heat of ice is 336 J g − 1, and specific heat capacity of water is 4 .2 J g − 1 L − 1 Assumption: No loss of energy in the result of mixing of 10 g ice at − 10 ∘ C with of water at 10 ∘ C. property for sale listowel irelandWebSolution please note that mixture temperature is 100 degree celsius.i took m gram of steam and heat lost by this amount of steam is used to raise temperature of 10 g of ice from … property for sale little horwoodWebJul 20, 2024 · What is the temperature of the substance and is the substance ice or water - 19778371. abishekcps abishekcps 20.07.2024 Physics Secondary School answered 10 g of ice at -10 C 10g of water at 10 C are getting mixed together . What is the temperature of the substance and is the substance ice or water See answers Advertisement Advertisement property for sale litchfieldWebAnswers (1) Amount of heat required to change ice at -20 degree to 0-degree celsius. = mass x specific heat * (T2-T1) = 10 gm x 2.1 J/gm/°C x (0°C - (-20° C)) = 420 Joules To convert ice to water at a constant temperature 0C, energy required : = Latent Heat x mass =3360 J Amount of heat required to change water a at 0 degree to 40 degree celsius: property for sale little burstead essexWebFeb 13, 2024 · Find the result of mixing 10 g of ice at -10οC with 10 g of water at 10οC.Specific heat capacity of ice=2.1 J g-1 K-1, specific latent heat of ice=336 J g-1 … lady rawhide 2022Web0.5kg of ice at -5degC is put into a vessel containing 2kg of water at 15deg C and mixed together, the result being a mixture of ice and water at 0degC.Calculate the final masses of ice and water, taking the water equivalent of the vessel as 0.15kg.The specific heat of ice is 2.04kJ/kg/K and the latent heat of fusion is 335kJ/kg. •. property for sale little haywood staffsWebDec 16, 2024 · Find the result of mixing 10 g of ice at - 10°C with 10 g of water at 10°C. Specific heat capacity of ice = 2.1 J g-1 K-1, specific latent heat of ice = 336 J g-1and … property for sale lithia florida